0.2x^2=-4x-12

Solution for 0.2x^2=-4x-12 equation:

0.2x^2=-4x-12

We move all terms to the left:

0.2x^2-(-4x-12)=0

We get rid of parentheses

0.2x^2+4x+12=0

a = 0.2; b = 4; c = +12;
Δ = b2-4ac
Δ = 42-4·0.2·12
Δ = 6.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-\sqrt{6.4}}{2*0.2}=\frac{-4-\sqrt{6.4}}{0.4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+\sqrt{6.4}}{2*0.2}=\frac{-4+\sqrt{6.4}}{0.4}
$